Why a 7 kg washer does not imply a particular motor wattage
Rated laundry capacity describes the dry textile mass an appliance is designed to wash under specified conditions. It does not uniquely determine motor power. Two machines with the same 7 kg rating can have different drum radii, transmission ratios, water volumes, acceleration targets, friction, control strategies and allowable spin speeds. Their motor requirements can therefore differ substantially. Selecting a motor by matching “7 kg” to a catalog wattage ignores the mechanics that actually create torque demand.
Separate three quantities before calculating: rotational inertia J, resisting torque Tload and required acceleration α. The inertia depends on how mass is distributed relative to the axis, not simply on total mass. A ring of mass m at radius r has J = mr²; a uniform solid disk has J = ½mr². Wet laundry is neither a rigid ring nor a uniform disk, and its distribution changes during the cycle. Engineering models should therefore be checked against measured spin-up behavior.
Build the shaft-torque model
The fundamental rotational equation is Tshaft = Jα + Tload. For a drum accelerated from rest to 800 rpm in 20 seconds, final angular speed is 800 × 2π/60 = 83.78 rad/s and average acceleration is 4.19 rad/s². If the effective inertia is assumed to be 0.18 kg·m², inertia torque is 0.75 N·m. Add an assumed 0.30 N·m of bearing and other resisting torque, and the simplified shaft requirement is approximately 1.05 N·m during that acceleration interval.
Mechanical power is P = Tω. At 800 rpm, a 1.05 N·m shaft torque corresponds to approximately 88 W of mechanical power. But this is not a sufficient motor rating by itself. Actual torque changes through the acceleration ramp; water drag, imbalance, friction and transmission losses vary. A candidate motor must also survive thermal duty and provide a suitable peak-torque margin. The example values are inputs to a transparent calculation, not measurements of a specific washer.
How the pulley ratio changes the motor requirement
Consider a belt drive with a motor pulley diameter of 40 mm and a drum pulley diameter of 160 mm. Neglecting slip, the motor turns four times faster than the drum. At 800 rpm drum speed, motor speed is about 3,200 rpm. For a belt efficiency assumed at 90%, the motor torque needed to deliver 1.05 N·m at the drum is approximately 1.05/(4 × 0.90) = 0.292 N·m. The corresponding mechanical motor output is about 98 W, consistent with the drum power divided by efficiency.
This shows why torque numbers without shaft location are misleading. A 1 N·m drum requirement is not the same as a 1 N·m motor-shaft requirement in a geared or belted system. Pulley diameter, belt wrap, slip and bearing loads all affect the practical result. A larger speed reduction reduces motor torque requirement but increases motor speed, which may alter acoustic behavior, available torque and efficiency.
| Calculation input | Illustrative value | Purpose |
|---|---|---|
| Target drum speed | 800 rpm | Defines final angular velocity |
| Acceleration time | 20 s | Defines average acceleration |
| Effective inertia | 0.18 kg·m² | Determines inertia torque |
| Resisting torque | 0.30 N·m | Adds friction and process load |
| Speed ratio | 4:1 | Converts drum to motor conditions |
| Assumed belt efficiency | 90% | Accounts for transmission loss |
Wash agitation needs a different load model
Spin acceleration is only one operating mode. During wash agitation, the drum or pulsator may reverse frequently, and fabric-water interaction creates an irregular load. A short peak-torque requirement can be much higher than steady agitation torque. Depending on machine architecture, the controller may limit acceleration, pause between reversals or modulate speed to manage current and textile motion. A single constant-load model will miss these transient demands.
For engineering tests, measure motor current and actual shaft speed over several representative wash programs. Include empty, nominal and heavy textile conditions and the most demanding permitted water fill. Compare the measured traces with the torque capability at the same speed and supply voltage. If the motor uses an inverter, current and thermal limits may restrict repeated acceleration even when a single start succeeds.
Peak torque is not the thermal rating
Many motor technologies can deliver short-duration torque above their continuous rating. That does not mean they can repeat the peak indefinitely. A simplified RMS-torque metric is Trms = √[Σ(Ti²ti)/Σti], useful when torque-related heating is approximately linked to current squared. For example, suppose a drive operates at 1.5 N·m for 5 seconds and 0.5 N·m for 15 seconds. The RMS torque is √[(1.5² × 5 + 0.5² × 15)/20] ≈ 0.866 N·m. The arithmetic mean torque is only 0.75 N·m, understating the heating-related significance of the high-torque interval.
RMS torque is a screening tool, not a complete thermal model. Motor efficiency, cooling airflow, winding resistance, iron loss and controller current waveforms also change with speed. A motor with adequate RMS torque on paper may still overheat if low-speed cooling is weak. Full-program winding-temperature measurement is necessary before a rating is finalized.
Unbalance introduces forces outside the simple torque equation
During spin, unevenly distributed wet laundry produces a radial excitation approximated by F = meω², where me is the effective eccentric mass-radius product. If 0.10 kg of effective eccentric mass is located 0.15 m from the axis at 800 rpm, force magnitude is about 0.10 × 0.15 × 83.78² ≈ 105 N. This force is not motor output torque; it is a lateral load transmitted through the basket, bearings, suspension and cabinet. Its square-law dependence on speed makes high-speed imbalance especially important.
The appliance controller may need to detect imbalance and reduce or postpone spin speed. Mechanical stability, bearing load and cabinet motion can set the practical speed limit before motor electrical power does. Engineers should therefore evaluate motor selection together with suspension design and imbalance management, rather than assuming a larger wattage solves a vibration problem.
Translate the calculation into a usable motor specification
For a production design, provide the candidate supplier with the drum or pulsator speed profile, inertia estimate, transmission ratio, maximum load torque, acceleration time, permitted start frequency, ambient temperature and power supply limits. Ask for continuous and peak torque capability across the operating speed range, not a single headline number. If a controller is included, specify its current limit and protective behavior.
Then validate at the appliance level. Instrument the motor and shaft, capture electrical input and speed, and record winding temperature after repeated cycles. Compare the worst-case measured points with the supplier's performance map. This method produces a defensible power and torque selection for each washer platform. The nominal kilogram capacity remains useful product information, but it is not an engineering shortcut for selecting the motor.
Why oversizing can also be a mistake
Specifying a motor with a very large peak-power margin may seem conservative, but it can increase purchase cost, package size and low-load inefficiency. For induction motors, operating far from the intended load point can produce poor power factor and unfavorable losses. For inverter-controlled drives, the motor and controller may both be oversized relative to the actual duty. A rational margin should cover uncertainty in inertia, wet-load friction, voltage variation and manufacturing tolerance without substituting for measurement.
It is useful to maintain a traceable calculation sheet with one row per operating phase: wash clockwise, pause, wash reverse, drain, spin ramp and steady spin. Each row should include duration, shaft speed, estimated torque and measured input current once prototypes exist. That format helps engineers discover whether the governing condition is starting torque, repetitive thermal load or steady high-speed operation. The answer determines whether to change motor size, pulley ratio, cooling, controller limits or the appliance program itself.

English
中文简体





